python3 题目 有四个数字：1、2、3、4，能组成多少个互不相同且无重复数字的三位数？各是多少？

counter=0
for i in range(1,5):
    for j in range(1,5):
        for k in range(1,5):
            if i !=j and j !=k and k !=i:
                print("{}{}{}".format(i,j,k),end=" ")
                counter +=1
print("")
print("共{}种组合".format(counter))

counter=0
from itertools import permutations
for i in permutations([1,2,3,4],3):
    print("{}{}{}".format(i[0],i[1],i[2]),end=" ")
    counter +=1
print("")
print("共{}种组合".format(counter))