Address:
https://pintia.cn/problem-sets/994805342720868352/problems/1071785408849047552
Description:
In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))
One thing for sure is that all the keys along any path from the root to a leaf in a max/min heap must be in non-increasing/non-decreasing order.
Your job is to check every path in a given complete binary tree, in order to tell if it is a heap or not.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (1), the number of keys in the tree. Then the next line contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
Output Specification:
For each given tree, first print all the paths from the root to the leaves. Each path occupies a line, with all the numbers separated by a space, and no extra space at the beginning or the end of the line. The paths must be printed in the following order: for each node in the tree, all the paths in its right subtree must be printed before those in its left subtree.
Finally print in a line
Max Heap
if it is a max heap, orMin Heap
for a min heap, orNot Heap
if it is not a heap at all.
Sample Input 1:
8 98 72 86 60 65 12 23 50
Sample Output 1:
98 86 23 98 86 12 98 72 65 98 72 60 50 Max Heap
Sample Input 2:
8 8 38 25 58 52 82 70 60
Sample Output 2:
8 25 70 8 25 82 8 38 52 8 38 58 60 Min Heap
Sample Input 3:
8 10 28 15 12 34 9 8 56
Sample Output 3:
10 15 8 10 15 9 10 28 34 10 28 12 56 Not Heap
Keys:
- 堆(Heap);
- 完全二叉树(Complete Binary Tree);
- 深度优先搜索(Depth First Search);
Attention:
- 完全二叉树采用静态存储,CBTree[1...n],从2/n+1开始为叶子结点;
- 采用RNL遍历
Code:
1 /* 2 Data: 2019-05-06 21:04:46 3 Problem: PAT_A1155#Heap Paths 4 AC: 48:00 5 */ 6 7 #include<cstdio> 8 #include<vector> 9 #include<cmath> 10 using namespace std; 11 const int M=1e3+10; 12 int heap[M], n, isMax=1,isMin=1; 13 vector<int> path; 14 15 void DFS(int fa, int root) 16 { 17 if(fa != 0) 18 { 19 if(heap[fa]>heap[root]) isMin=0; 20 if(heap[fa]<heap[root]) isMax=0; 21 } 22 path.push_back(heap[root]); 23 if(root>n/2) 24 { 25 for(int i=0; i<path.size(); i++) 26 printf("%d%c", path[i], i==path.size()-1?'n':' '); 27 return; 28 } 29 if(root*2+1<=n) 30 { 31 DFS(root, root*2+1); 32 path.pop_back(); 33 } 34 if(root*2<=n) 35 { 36 DFS(root, root*2); 37 path.pop_back(); 38 } 39 } 40 41 int main() 42 { 43 #ifdef ONLINE_JUDGE 44 #else 45 freopen("Test.txt", "r", stdin); 46 #endif 47 48 scanf("%d", &n); 49 for(int i=1; i<=n; i++) 50 scanf("%d", &heap[i]); 51 DFS(0,1); 52 if(isMax) 53 printf("Max Heapn"); 54 else if(isMin) 55 printf("Min Heapn"); 56 else 57 printf("Not Heapn"); 58 59 return 0; 60 }
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