题目链接： http://acm.hdu.edu.cn/showproblem.php?pid=1002
题目描述
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
Sample Input
2
1 2
112233445566778899 998877665544332211
Sample Output
Case 1:
1 + 2 = 3
Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110
题目要求：大数加法
思路：就是简单的大数高精而已，且不用压位操作，不值得大费周章的用c去写，直接上BigInteger。
Code：
import java.math.BigInteger;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner s1=new Scanner (System.in);
int n;
n=s1.nextInt();
for(int i=0;i<n;i++){
if((i+1) != 1){
System.out.println();
}
BigInteger a,b;
a=s1.nextBigInteger();
b=s1.nextBigInteger();
System.out.println("Case "+(i+1)+":");
System.out.println(a+" + "+b+" = "+a.add(b));
}
}
}
文章来源: 博客园
- 还没有人评论，欢迎说说您的想法！
客服
