用C语言编写一个简单的可以进行加减乘除运算混合运算的计算器的方法,利用运算符做为swich case 语句条件,实现简单程序的编写;并且对输入的运算做判断,除数为零也需做判断;
# include <stdio.h> int main() { char operator; double firstNumber,secondNumber; printf("输入操作符 (+, -, *,/): "); scanf("%c", &operator); printf("输入两个数字: "); scanf("%lf %lf",&firstNumber, &secondNumber); switch(operator) { case '+': printf("%.1lf + %.1lf = %.1lf",firstNumber, secondNumber, firstNumber + secondNumber); break; case '-': printf("%.1lf - %.1lf = %.1lf",firstNumber, secondNumber, firstNumber - secondNumber); break; case '*': printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber * secondNumber); break; case '/': printf("%.1lf / %.1lf = %.1lf",firstNumber, secondNumber, firstNumber / secondNumber); break; // operator doesn't match any case constant (+, -, *, /) default: printf("Error! operator is not correct"); } return 0; }
另外如果你想更好的提升你的编程能力,学好C语言C++编程!弯道超车,快人一步!笔者这里或许可以帮到你~
欢迎转行和学习编程的伙伴,利用更多的资料学习成长比自己琢磨更快哦!
免费学习资料:
内容来源于网络如有侵权请私信删除
文章来源: 博客园
- 还没有人评论,欢迎说说您的想法!